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(3x-4)(2x+1)+4=6x^2-8x+15
We move all terms to the left:
(3x-4)(2x+1)+4-(6x^2-8x+15)=0
We get rid of parentheses
-6x^2+(3x-4)(2x+1)+8x-15+4=0
We multiply parentheses ..
-6x^2+(+6x^2+3x-8x-4)+8x-15+4=0
We add all the numbers together, and all the variables
-6x^2+(+6x^2+3x-8x-4)+8x-11=0
We get rid of parentheses
-6x^2+6x^2+3x-8x+8x-4-11=0
We add all the numbers together, and all the variables
3x-15=0
We move all terms containing x to the left, all other terms to the right
3x=15
x=15/3
x=5
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